Aufgabe 06-1
- Tom Liebing
Owned by Tom Liebing
Gegeben ist die folgende Dioden-Schaltung mit zwei realen Dioden, zwei Widerständen und zwei Spannungsquellen.
Sie kennen die folgenden Werte: ' aria-hidden='true'%3e %3cg transform='translate(167%2c0)'%3e %3cg transform='translate(-11%2c0)'%3e %3cg transform='translate(0%2c-50)'%3e %3cuse xlink:href='%23E1-MJMATHI-52' x='0' y='0'%3e%3c/use%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-31' x='1074' y='-213'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-3D' x='1491' y='0'%3e%3c/use%3e %3cg transform='translate(2547%2c0)'%3e %3cuse xlink:href='%23E1-MJMAIN-31'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-35' x='500' y='0'%3e%3c/use%3e %3c/g%3e %3cg transform='translate(3715%2c0)'%3e %3cuse xlink:href='%23E1-MJMAIN-6B' x='0' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-3A9' x='528' y='0'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3B' x='4966' y='0'%3e%3c/use%3e %3cg transform='translate(5689%2c0)'%3e %3cuse xlink:href='%23E1-MJMATHI-52' x='0' y='0'%3e%3c/use%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-32' x='1074' y='-213'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3D' x='7180' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-38' x='8236' y='0'%3e%3c/use%3e %3cg transform='translate(8903%2c0)'%3e %3cuse xlink:href='%23E1-MJMAIN-6B' x='0' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-3A9' x='528' y='0'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3B' x='10154' y='0'%3e%3c/use%3e %3cg transform='translate(10877%2c0)'%3e %3cuse xlink:href='%23E1-MJMATHI-55' x='0' y='0'%3e%3c/use%3e %3cg transform='translate(683%2c-150)'%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-44' x='0' y='0'%3e%3c/use%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-31' x='764' y='0'%3e%3c/use%3e %3c/g%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3D' x='12833' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-30' x='13889' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-2C' x='14390' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-37' x='14835' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-56' x='15502' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-3B' x='16253' y='0'%3e%3c/use%3e %3cg transform='translate(16975%2c0)'%3e %3cuse xlink:href='%23E1-MJMATHI-55' x='0' y='0'%3e%3c/use%3e %3cg transform='translate(683%2c-150)'%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-44' x='0' y='0'%3e%3c/use%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-32' x='764' y='0'%3e%3c/use%3e %3c/g%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3D' x='18931' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-30' x='19988' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-2C' x='20488' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-37' x='20933' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-56' x='21600' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-3B' x='22351' y='0'%3e%3c/use%3e %3cg transform='translate(23074%2c0)'%3e %3cuse xlink:href='%23E1-MJMATHI-55' x='0' y='0'%3e%3c/use%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-31' x='966' y='-213'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3D' x='24489' y='0'%3e%3c/use%3e %3cg transform='translate(25545%2c0)'%3e %3cuse xlink:href='%23E1-MJMAIN-31'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-30' x='500' y='0'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-56' x='26713' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-3B' x='27463' y='0'%3e%3c/use%3e %3cg transform='translate(28186%2c0)'%3e %3cuse xlink:href='%23E1-MJMATHI-55' x='0' y='0'%3e%3c/use%3e %3cuse transform='scale(0.707)' xlink:href='%23E1-MJMAIN-32' x='966' y='-213'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-3D' x='29602' y='0'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-2212' x='30658' y='0'%3e%3c/use%3e %3cg transform='translate(31436%2c0)'%3e %3cuse xlink:href='%23E1-MJMAIN-31'%3e%3c/use%3e %3cuse xlink:href='%23E1-MJMAIN-35' x='500' y='0'%3e%3c/use%3e %3c/g%3e %3cuse xlink:href='%23E1-MJMAIN-56' x='32604' y='0'%3e%3c/use%3e %3c/g%3e %3c/g%3e %3c/g%3e %3c/g%3e %3c/svg%3e)
Ermitteln Sie, welche der Dioden leiten und berechnen Sie die Ströme durch die beiden Dioden.
Institut für Mechatronik im Maschinenbau (iMEK), Eißendorfer Straße 38, 21073 Hamburg