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body--uriencoded--\begin%7Bgather*%7D R_%7BAB%7D=R_1 \,%7C%7C\, R_2 %7C%7C R_%7B34567%7D = \frac%7B1%7D%7B\frac%7B1%7D%7B10\Omega%7D+\frac%7B1%7D%7B10\Omega%7D+\frac%7B1%7D%7B26,09\Omega%7D%7D = 4,20 \Omega \end%7Bgather*%7D

Lösung 1.3 - CD:

Verschaltung erkennen:

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body--uriencoded--R_%7BCD%7D= R_4\,%7C%7C\,(R_3+(R_1%7C%7CR_2))\,%7C%7C\,(R_6+(R_5%7C%7CR_7))

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body--uriencoded--\begin%7Bgather*%7D R_%7B123%7D=20\Omega+ \frac%7B1%7D%7B\frac%7B1%7D%7B10\Omega%7D+\frac%7B1%7D%7B10\Omega%7D%7D=25\Omega \end%7Bgather*%7D

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body--uriencoded--\begin%7Bgather*%7D R_%7B567%7D= 5\Omega + \frac%7B1%7D%7B\frac%7B1%7D%7B5\Omega%7D+\frac%7B1%7D%7B15\Omega%7D%7D=8,75\Omega \end%7Bgather*%7D

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body--uriencoded--\begin%7Bgather*%7D R_%7BCD%7D= \frac%7B1%7D%7B\frac%7B1%7D%7B20\Omega %7D+\frac %7B1%7D%7B25\Omega %7D+\frac %7B1%7D%7B8,75\Omega %7D %7D = 4,90\Omega \end%7Bgather*%7D


Aufgabe 03-2:

Es ist die untenstehende Schaltung mit folgenden Werten gegeben:

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